Introduction

Hi everyone In this article we will create a javascript program to check number is Even or Odd in Javascript. To achieve this, divide the number by 2, then determine if it is divisible or not. If a number is exactly divisible by 2, it is an even number; otherwise, it is an odd number.

Here are the Methods to solve the above-mentioned problem,

• Method 1: Using Brute Force

• Method 2: Using Ternary Operator

Flow Chart

Method: 1 Using Brute Force

This method simply checks if the given input integer is divisible by 2 or not. If it’s divisible then print Even or Odd otherwise.

Algorithm

• step 1: Input Number

• step 2: check whether the number is divisible by 2

• step 3: if(number % 2 == 0)

  • if yes print "Even Number"

  • if no print "Odd Number"

• step 4: stop

Javascript Code

//method 1 Brute Force
let number = 20;
if(number %2 == 0){
    console.log(`${number} is Even Number`);
}else{
    console.log(`${number} is Odd Number`);
}

Output

20 is Even Number

Method: 2 Using Ternary Operator

This Method uses the ternary operator to check if the integer input is divisible by 2, If true print Even or Odd otherwise.

Syntax:

(condition) ? (if True : Action) : (if false : Action);

Algorithm

• step 1: Input Number

• step 2: check whether the number is divisible by 2 or not using the ternary operator

• step 3: (number % 2) ? ("Even number") : ("Odd number")

• step 4: stop

Javascript Code

//Method 2 ternary operator
let number2 = 21;
let result = number2% 2 == 0 ? ' is Even Number': ' is Odd Number';
console.log(number2+result)

Output

21 is Odd Number